Max Cost Calculator Solution

This Python program is designed to calculate the maximum cost based on three inputs: an array of costs, an array of labels, and a daily count. The costs and labels are associated with each other, and the daily count is used to determine the frequency of calculation. The labels can be 'legal' or 'illegal', and the 'illegal' labels are ignored in the calculation.

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Here is the Max Cost Calculator Solution from HackerRank using CodeRankGPT:

The solution works by iterating over the cost and labels arrays simultaneously. For each pair, the current cost is incremented by the cost value. If the label is 'illegal', the program continues to the next iteration without further action. If the label is not 'illegal', the current count is incremented. When the current count reaches the daily count, the maximum of the current maximum and the current cost is calculated and stored as the new maximum. The current count and current cost are then reset to zero. The function returns the maximum cost calculated.


import math
import os
import random
import re
import sys

def maxCost(cost, labels, dailyCount):
    ans = 0
    cur_cnt = 0
    cur_cost = 0
    for c, l in zip(cost, labels):
        cur_cost += c
        if l == 'illegal':
            continue
        cur_cnt += 1
        if cur_cnt == dailyCount:
            ans = max(ans, cur_cost)
            cur_cnt = 0
            cur_cost = 0
    return ans

if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')

    cost_count = int(input().strip())

    cost = []

    for _ in range(cost_count):
        cost_item = int(input().strip())
        cost.append(cost_item)

    labels_count = int(input().strip())

    labels = []

    for _ in range(labels_count):
        labels_item = input()
        labels.append(labels_item)

    dailyCount = int(input().strip())

    result = maxCost(cost, labels, dailyCount)

    fptr.write(str(result) + '\n')

    fptr.close()

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