The problem context involves taking a string input from the user and determining the frequency of each digit (0-9) present in the string. The string can contain any characters, but the program is specifically interested in the digits.
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The solution approach involves initializing an array of size 10 to keep track of the count of each digit. The program then iterates over the input string, and for each character, it checks if it is a digit by comparing its ASCII value. If it is a digit, it increments the corresponding index in the digits array. Finally, it prints out the count of each digit.
#include
#include
#include
#include
int main() {
char str[1000];
int digits[10] = { 0 };
scanf("%s", str);
for (int i = 0; i < strlen(str); i++) {
// Checking with ASCII decimal representation
if (str[i] >= 48 && str[i] <= 57)
digits[str[i] - 48]++;
}
// Print digits array elements
for (int i = 0; i < 10; i++) {
printf("%d ", digits[i]);
}
return 0;
}
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