For Loop In C Problem

The problem context involves reading two integers from user input and printing each number in the range from the first to the second number, inclusive. If the number is between 1 and 9, it should be printed as a word (e.g., 'one', 'two', etc.). If the number is greater than 9 and is even, it should print 'even'. If the number is greater than 9 and is odd, it should print 'odd'.

Secure your next interview 🎯

CodeRankGPT is a tool powered by GPT-4 that quietly assists you during your coding interview, providing the solutions you need.
In real-time and absolutely undetectable 🥷

Here is the For Loop In C Problem HackerRank solution using CodeRankGPT:

The solution approach involves using a for loop to iterate through the range of numbers from the first to the second number, inclusive. An array of strings is used to map numbers from 1 to 9 to their corresponding word. If the number is between 1 and 9, the corresponding word is printed. If the number is greater than 9, it checks if the number is even or odd using the modulus operator and prints 'even' or 'odd' accordingly.


#include 

int main()
{
    int a, b;
    scanf("%d\n%d", &a, &b);
    // Complete the code.
    const char* word[] = { "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };
    for (int i = a; i <= b; i++) {
        if (i >= 1 && i <= 9) printf("%s\n", word[i - 1]);
        else if (i > 9 && i % 2 == 0) printf("even\n");
        else if (i > 9 && i % 2 == 1) printf("odd\n");
    }

    return 0;
}

If you have a HackerRank coding test coming up, you can use CodeRankGPT to your advantage. It will assist you during your interview and help ensure you get the job.

AI is here now, and other candidates might be using it to get ahead and win the job. 🧐

Submission Successful

The form has been successfully submitted.

Built on Unicorn Platform