CodeRankGPT -
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The problem context involves creating a phone directory where each entry consists of a name and a phone number. The directory should be able to handle queries, returning the phone number for a given name if it exists in the directory, or 'Not found' if it doesn't.
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The solution approach involves using a HashMap data structure in Java, where the name is the key and the phone number is the value. The program reads the number of entries from the user, then for each entry, it reads the name and phone number and adds them to the HashMap. It then enters a loop where it reads queries from the user. For each query, it checks if the name exists in the HashMap. If it does, it prints the name and phone number. If it doesn't, it prints 'Not found'.
/**
*
*/
package com.javaaid.hackerrank.solutions.languages.java.datastructures;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
/**
*
*/
public class JavaMap {
public static void main(String[] argh) {
Scanner in = new Scanner(System.in);
Map hmap = new HashMap();
int n = in.nextInt();
in.nextLine();
for (int i = 0; i < n; i++) {
String name = in.nextLine();
int phone = in.nextInt();
hmap.put(name, phone);
in.nextLine();
}
while (in.hasNext()) {
String s = in.nextLine();
if (hmap.containsKey(s)) {
System.out.println(s + "=" + hmap.get(s));
} else {
System.out.println("Not found");
}
}
in.close();
}
}
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