The problem at hand involves generating a sequence of Fibonacci numbers and then applying a cube function to each number in the sequence. The Fibonacci sequence is a series of numbers in which each number is the sum of the two preceding ones, usually starting with 0 and 1. The cube function, on the other hand, raises a number to the power of three.
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The solution uses Python's built-in 'map' and 'lambda' functions to solve the problem. The 'lambda' function is used to define a simple function to cube a number, and the 'map' function is used to apply this cube function to each number in the Fibonacci sequence. The Fibonacci sequence is generated using a simple iterative approach, where each number is the sum of the two preceding ones.
cube = lambda x: x * x * x
def fibonacci(n):
ar = [0, 1]
if n < 2:
return ar[:n]
for i in range(2, n):
ar.append(ar[i - 1] + ar[i - 2])
return ar
if __name__ == "__main__":
n = int(input())
print(list(map(cube, fibonacci(n))))
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