The problem context involves checking if a number is prime or not. A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. The task is to create a method that takes a list of integers as input and prints out the prime numbers from the list.
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The solution approach involves iterating over the list of integers. For each integer, it checks if it is less than or equal to 3 and greater than 1, if so, it is considered as a prime number. For integers greater than 3, it checks if it has any divisors other than 1 and itself by iterating from 2 to the square root of the number. If no divisors are found, the number is considered prime. The prime numbers are then printed out.
/**
*
*/
package com.javaaid.hackerrank.solutions.languages.java.advanced;
/**
*
*/
public class PrimeChecker {
public void checkPrime(int... num) {
String str = "";
for (int n : num) {
boolean found = true;
if (n <= 3 && n > 1) {
str += n + " ";
} else {
for (int i = 2; i <= Math.sqrt(n); i++) {
if (n % i == 0) {
found = false;
break;
}
}
if (found && n != 1) {
str += n + " ";
}
}
}
System.out.println(str);
}
}
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