Set .discard(), .remove() & .pop() solved

This Python script is designed to manipulate a set of integers. The user can input a series of commands to perform different operations on the set, such as discarding, removing, or popping elements. The script then prints the sum of the remaining elements in the set.

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Here is the Set .discard(), .remove() & .pop() solved HackerRank solution using CodeRankGPT:

The script first takes the number of elements and the elements themselves as input from the user. It then takes the number of commands the user wants to execute. For each command, it checks if the command is to pop an element, in which case it does so without any further checks. If the command is not to pop, it takes the value to be operated on and the operation to be performed as input. If the operation is 'discard', it discards the value from the set if it exists, otherwise it does nothing. If the operation is 'remove', it removes the value from the set if it exists, otherwise it raises a KeyError. Finally, it prints the sum of the remaining elements in the set.


number_of_elements = int(input())
elements = set(map(int, input().split()))
number_of_commands = int(input())
for _ in range(number_of_commands):
    cmd = list(input().split())
    if len(cmd) == 1:
        elements.pop()
    else:
        value = int(cmd[1])
        operation = cmd[0]
        if operation == 'discard':
            elements.discard(value)
        else:
            elements.remove(value)
print(sum(elements))

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