In the context of a coding challenge platform, hackers submit solutions to various challenges. Each challenge has a difficulty level and each submission has a score. The problem here is to identify hackers who have made more than one submission where the score matches the difficulty level of the challenge.
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The solution approach involves joining four tables: submissions, challenges, difficulty, and hackers. The join conditions ensure that only those records where the submission's score matches the challenge's difficulty level are considered. The result is then grouped by hacker ID and name, and filtered to include only those hackers who have more than one such submission. The final result is ordered by the number of such submissions in descending order, and by hacker ID in ascending order.
SELECT H.hacker_id,
H.name
FROM submissions S
JOIN challenges C
ON S.challenge_id = C.challenge_id
JOIN difficulty D
ON C.difficulty_level = D.difficulty_level
JOIN hackers H
ON S.hacker_id = H.hacker_id
AND S.score = D.score
GROUP BY H.hacker_id,
H.name
HAVING Count(S.hacker_id) > 1
ORDER BY Count(S.hacker_id) DESC,
S.hacker_id ASC;
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